Material Properties: Teflon

Data Available:

 
Thermal Conductivity
Specific Heat
UNITS W/(m-K) J/(kg-K)
a 2.7380 31.88256
b -30.677 -166.51949
c 89.430 352.01879
d -136.99 -393.44232
e 124.69 259.98072
f -69.556 -104.61429
g 23.320 24.99276
h -4.3135 -3.20792
i 0.33829 0.16503
data range
4-300 4-300
equation range
4-300 4-300
curve fit % error relative to data 5 1.5
Curve fit equation of the form:
log10 y = a+b(log10T) + c(log10T) 2 + d(log10T) 3 + e(log10T) 4 + f(log10T) 5 + g(log10T) 6 + h(log10T) 7 + i(log10T) 8


Solves as:
y = 10
a+b(log10T) + c(log10T) 2 + d(log10T) 3 + e(log10T) 4 + f(log10T) 5 + g(log10T) 6 + h(log10T) 7 + i(log10T) 8

Where: Coefficients a - i are summarized in the appropriate table and T is the temperature in K (x-axis), and y is the property to solve for.

See References

  Linear expansion
.Units
[(L-L293)/L293] x 105 unitless, eg. m/m
a
-2.125E3
b
-8.201E-1
c
6.161E-2
d
-3.171E-4
e
6.850E-7
Tlow (K)
NA
f>
NA
data range (K)
4-300
equation range (K)
4-300
curve fit % error relative to data
2
equation of the form:
y = a + bT + cT 2 + dT 3 + eT 4
   >T > Tlow
y = f 
   T < Tlow
solves as expected: Where: Coefficients a-e are summarized in the appropriate table and T is the temperature in K (x-axis), and y is the property to solve for.

See References

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